6x+(2x^2/x)+3(2x+4)=15x+(3x+1/3x+1)

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Solution for 6x+(2x^2/x)+3(2x+4)=15x+(3x+1/3x+1) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*(2*x+4)+6*x+(2*x^2)/x = 15*x+3*x+(1/3)*x+1 // - 15*x+3*x+(1/3)*x+1

3*(2*x+4)+6*x+(2*x^2)/x-(15*x)-(3*x)-((1/3)*x)-1 = 0

3*(2*x+4)+6*x+(2*x^2)/x-15*x-3*x+(-1/3)*x-1 = 0

3*(2*x+4)+6*x+2*x-15*x-3*x-x/3-1 = 0

(3^2*(2*x+4))/3+(3*6*x)/3+(2*3*x)/3+(-15*3*x)/3+(-3*3*x)/3-x/3+(-1*3)/3 = 0

3^2*(2*x+4)+3*6*x+2*3*x-15*3*x-3*3*x-x-1*3 = 0

36*x+6*x-45*x-9*x-x-3+36 = 0

42*x-45*x-9*x-x-3+36 = 0

36-3*x-9*x-x-3 = 0

36-12*x-x-3 = 0

36-13*x-3 = 0

33-13*x = 0

(33-13*x)/3 = 0

(33-13*x)/3 = 0 // * 3

33-13*x = 0

33-13*x = 0 // - 33

-13*x = -33 // : -13

x = -33/(-13)

x = 33/13

x = 33/13

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